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This booklet is filled with transparent revision notes and examination perform questions for AS Maths scholars. It covers the C1, C2, S1, M1 and D1 modules for the Edexcel examination, and it’s effortless to learn and revise from - everything’s defined easily and punctiliously. each few pages there are quickly warm-up questions, a few exam-style questions and on the finish of every module there are perform examination papers (answers on the back). There’s additionally a sprinkling of jokes to lighten the temper. It’s precisely what you want to organize in your tests!
Read Online or Download AS-Level Mathematics Edexcel: Complete Revision & Practice PDF
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Additional resources for AS-Level Mathematics Edexcel: Complete Revision & Practice
Find: a) the speed of the car after 8 seconds and b) the car’s acceleration during this period. a) You can work out the speed by calculating the gradient of the curve s = 2t2. 200 distance (s) 160 80 When t = 8, ds = 32 dt Differentiate to give: ds = 4t dt So, the car is travelling at 32 ms–1 after 8 seconds. e. it is the gradient of v = 4t). 0 2 4 6 8 10 time ( t ) 2 So differentiate again to find the acceleration: d s2 = 4 dt This means that the car’s acceleration during this period is 4 ms–2 This is called a second-order derivative — because you’ve differentiated twice Help me Differentiation — You’re my only hope...
Make sure you rearrange them as ‘ax + by = c’. 4 + 5y =- 3x - 2x = 9 - 3y rearrange as ax + by = c 3x + 5y =- 4 - 2x + 3y = 9 Solving them by Elimination Elimination is a lovely method. It’s really quick when you get the hang of it — you’ll be doing virtually all of it in your head. EXAMPLE: A 1 3x + 5y =- 4 2 - 2x + 3y = 9 To get the x’s to match, you need to multiply the first equation by 2 and the second by 3: 1 ×2 6x + 10y = - 8 2 ×3 - 6x + 9y = 27 Add the equations together to eliminate the x’s.
1) Negative values of ‘a’ reflect the basic shape in the x-axis. e. |a| > 1) the graph is stretched vertically. e. |a| < 1) the graph is squashed vertically. e. y = –2x3 + 8x. e. y = 31 x 3 - 43 x . Writing ‘ax’ instead of ‘x’ stretches, squeezes or reflects the graph horizontally. 1) Negative values of ‘a’ reflect the basic shape in the y-axis. e. if |a| > 1) the graph is squashed horizontally. e. if |a| < 1) the graph is stretched horizontally. e. y = x - 2x . e. y = –27x3 + 12x. 33 C1 SectionMain 4 — Practice Heading Questions There you go then...